Analog Intuition

Loop-gain Bode

\(T = K\cdot F/(1+s/\omega_p)\) · plant is one pole · 0 dB is crossover

\(f_c\) → —
\(|T|\) at DC → —

T(s) = K · F / (1 + s/ωp). dB add on the Bode. K lifts |T| without moving the plant pole.

Break the loop · T = Vreturn / Vtest Break the loop · T = Vreturn / Vtest Vtest C(s) Comp P(s) Plant Vout F(s) FB Vreturn open
Opened at Σ. \(T = V_{\mathrm{return}}/V_{\mathrm{test}} = P\,C\,F\).

Bode of T · 10 Hz–1 MHz

|T| (dB) Phase 0 dB fc
\(T\) vs closed-loop \(T_{\mathrm{cl}}\)

Forward path \(L=CP\). Closed-loop from reference to output:

\[ T_{\mathrm{cl}} = \frac{V_{\mathrm{out}}}{V_{\mathrm{ref}}} = \frac{L}{1+LF} \qquad T = L F = P\,C\,F \]

We shape \(T\) because it is what a network analyzer measures when you break the loop. \(K\) in textbooks is \(T(s)=K\,P\,C\,F\) — a bag for modulator gain, sense gain, and so on. It is not a third capacitor. Sliding \(K\) does not move pole/zero frequencies; it only moves crossover. Instability is \(1+T=0\): unity gain and −180° together. That reading is the next page.