Part 5d · Voltage Regulation
Key point: conduction loss is \(I^2R\) while the switch is ON. Switching loss happens in the short overlap when \(V_{\mathrm{DS}}\) and \(I_D\) are both large. That overlap exists because a finite gate current must charge \(C_{\mathrm{GS}}\) and, during the Miller interval, \(C_{\mathrm{GD}}\).
\(I_G=(V_{\mathrm{DRV}}-V_{\mathrm{GS}})/(R_{\mathrm{drive}}+R_{\mathrm{g}})\) · gold line is this instant
Device · which capacitor \(I_G\) is filling
Turn-on · \(V_{\mathrm{GS}}\), \(I_D\), \(V_{\mathrm{DS}}\) vs time
Datasheet · \(V_{\mathrm{GS}}\) vs \(Q_g\)
\(I_G=(V_{\mathrm{DRV}}-V_{\mathrm{GS}})/(R_{\mathrm{drive}}+R_{\mathrm{g}})\). \(C_{\mathrm{GS}}\) charges exponentially; Miller is the one interval with constant \(I_G\) (stuck \(V_{\mathrm{GS}}\)). \(E_{\mathrm{sw}}\) is the \(V\times I\) overlap only. Gate-drive heat is \(Q_g V_{\mathrm{DRV}} f_{\mathrm{sw}}\), burned in the two resistors — \(R_{\mathrm{g}}\) does not change that energy, only the overlap. Cartoon constant caps, not \(C_{\mathrm{rss}}(V)\).
Try it: Same 0–30 nC frame on every FET. Low \(Q_g\) is a small die (higher \(R_{\mathrm{DS(on)}}\)). Low \(R\) is a wide die (more gate charge). 10 V class vs High-voltage moves \(V_{\mathrm{DD}}\) — watch the Miller shelf and \(V_{\mathrm{DS,on}}=I_D R_{\mathrm{DS(on)}}\). Raise \(R_{\mathrm{g}}\) to 5 Ω: \(I_G\) falls, time stretches, \(E_{\mathrm{sw}}\) climbs, \(Q_g\) does not.
Full converter loss stack: MOSFET Efficiency Tool.