Analog Intuition

Part 5d · Voltage Regulation

MOSFET switching · charging \(C_{\mathrm{GS}}\) and \(C_{\mathrm{GD}}\)

Key point: conduction loss is \(I^2R\) while the switch is ON. Switching loss happens in the short overlap when \(V_{\mathrm{DS}}\) and \(I_D\) are both large. That overlap exists because a finite gate current must charge \(C_{\mathrm{GS}}\) and, during the Miller interval, \(C_{\mathrm{GD}}\).

Lab · Scrub a turn-on · watch which cap is charging

\(I_G=(V_{\mathrm{DRV}}-V_{\mathrm{GS}})/(R_{\mathrm{drive}}+R_{\mathrm{g}})\) · gold line is this instant

Delay
Through the event

Device · which capacitor \(I_G\) is filling

Turn-on · \(V_{\mathrm{GS}}\), \(I_D\), \(V_{\mathrm{DS}}\) vs time

Datasheet · \(V_{\mathrm{GS}}\) vs \(Q_g\)

Scene
\(Q_g\) so far
\(Q_{\mathrm{GD}}\)
\(t_r+t_f\)
\(E_{\mathrm{sw}}\)
\(P_{\mathrm{sw}}\)
\(P_{\mathrm{gate}}\)
\(V_{\mathrm{DS,on}}\)
\[ t_f=Q_{\mathrm{GD}}/I_G \]
\[ E_{\mathrm{sw}}\approx\tfrac12 V_{\mathrm{DD}}I_D t_r+\tfrac12 I_D(V_{\mathrm{DD}}+V_{\mathrm{on}})t_f \]

\(I_G=(V_{\mathrm{DRV}}-V_{\mathrm{GS}})/(R_{\mathrm{drive}}+R_{\mathrm{g}})\). \(C_{\mathrm{GS}}\) charges exponentially; Miller is the one interval with constant \(I_G\) (stuck \(V_{\mathrm{GS}}\)). \(E_{\mathrm{sw}}\) is the \(V\times I\) overlap only. Gate-drive heat is \(Q_g V_{\mathrm{DRV}} f_{\mathrm{sw}}\), burned in the two resistors — \(R_{\mathrm{g}}\) does not change that energy, only the overlap. Cartoon constant caps, not \(C_{\mathrm{rss}}(V)\).

Try it: Same 0–30 nC frame on every FET. Low \(Q_g\) is a small die (higher \(R_{\mathrm{DS(on)}}\)). Low \(R\) is a wide die (more gate charge). 10 V class vs High-voltage moves \(V_{\mathrm{DD}}\) — watch the Miller shelf and \(V_{\mathrm{DS,on}}=I_D R_{\mathrm{DS(on)}}\). Raise \(R_{\mathrm{g}}\) to 5 Ω: \(I_G\) falls, time stretches, \(E_{\mathrm{sw}}\) climbs, \(Q_g\) does not.

Full converter loss stack: MOSFET Efficiency Tool.