Analog Intuition

Part 3 · Output Noise

Adding Noise Sources

Uncorrelated sources add in power — not by adding Vrms on a napkin.

Two sources → one node

Independent Gaussian noise · 10 ms · v₁ v₂ sum naive pk-pk

1 · Sources (overlaid)
2 · Sum v₁+v₂ (real) + naive pk-pk
3 · Histogram of sum
σ_A (spec)
σ_B (spec)
σ naive (A+B) Wrong — don’t add Vrms
σ RSS √(A² + B²)
σ measured Accumulated on sum
Triggers 0

Pk-pk trap — peaks don’t add either; specs use Vrms

Pk-pk (sum) This capture
Pk-pk naive (A+B) Wrong guess

Scope auto-scale follows the RSS total so large sources stay on-screen.

Read left → right: (1) Blue v₁ and magenta v₂ are independent. (2) Gold is the real sum — red dashed lines are naive pk-pk (this capture’s pk-pk of A plus pk-pk of B), usually way outside the sum. Green dotted = actual sum pk-pk this capture. (3) Histogram of the sum → σ tracks RSS, not naive A+B Vrms. Try 10 + 10 for a clear gap between red and the gold waveform.

Show the algebra

Instantaneous voltages do add: \(v = v_1 + v_2\). For zero-mean uncorrelated noise, average the squares:

\[ \overline{v^2} = \overline{v_1^2} + \overline{v_2^2} + \overline{2 v_1 v_2} \]

The cross term averages to zero when sources are uncorrelated. Then take the square root to get back to volts:

\[ V_\mathrm{rms} = \sqrt{\overline{v^2}} = \sqrt{V_{1,\mathrm{rms}}^2 + V_{2,\mathrm{rms}}^2} \]
Term Accumulated mean square
\(\overline{v_1^2}\)
\(\overline{v_2^2}\)
\(\overline{2 v_1 v_2}\)
\(\overline{(v_1+v_2)^2}\)
\(\sqrt{\overline{(v_1+v_2)^2}}\)
RSS \(\sqrt{A^2+B^2}\)

Spec: \(V_{1,\mathrm{rms}} =\) , \(V_{2,\mathrm{rms}} =\) . Correlated sources would keep a non-zero cross term — not covered here.

Why this matters on the bench

An LDO after a switcher, or two noise contributors in the same band, combine as root-sum-square — not a straight sum of scope pk-pk numbers or Vrms guesses.